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Ex 14.1, 2 (vii) - Chapter 14 Class 8 Factorisation

Last updated at Dec. 26, 2018 by

Ex 14.1, 2 (vii) - Factorise 10 a^2 - 15 b^2 + 20 c^2 - Teachoo

Ex 14.1, 2 (vii) - Chapter 14 Class 8 Factorisation - Part 2
Ex 14.1, 2 (vii) - Chapter 14 Class 8 Factorisation - Part 3

Transcript

Ex 14.1, 2 (Method 1) Factorise the following expressions. (vii) 10 𝑎^2 – 15 𝑏^2 + 20 𝑐^2 Now, 10𝑎^2= 10 × 𝑎^2 = 2 × 5 × 𝑎^2 = 2 × 5 × a × a 15𝑏^2 = 15 × 𝑏^2 = 3 × 5 × 𝑏^2 = 2 × 5 × b × b 20𝑐^2 = 20 × 𝑐^2 = 2 × 2 × 5 × 𝑐^2 = 2 × 2 × 5 × c × c So, 5 is the common factor. 10𝑎^2 – 15𝑏^2 + 20𝑐^2 = (2 × 5 × a × a) − (3 × 5 × b × b) + (2 × 2 × 5 × c × c) Taking 5 common = 5 × ((2 × a × a) − (3 × b × b) + (2 × 2 × c × c)) = 5 × (2𝑎^2 − 3𝑏^2 + 4𝑐^2) = 5 (2𝒂^𝟐 − 3𝒃^𝟐 + 4𝒄^𝟐) Ex 14.1, 2 (Method 2) Factorise the following expressions. (vii) 10 𝑎^2 – 15 𝑏^2 + 20 𝑐^2 10 𝑎^2 – 15 𝑏^2 + 20 𝑐^2 = (5 × 2) 𝑎^2 − (5 × 3 ) 𝑏^2 + (5 × 4) 𝑐^2 Taking 5 common, = 5 (2𝒂^𝟐 − 3𝒃^𝟐 + 4𝒄^𝟐)

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.