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  1. Chapter 14 Class 8 Factorisation
  2. Serial order wise

Transcript

Ex 14.1, 2 (Method 1) Factorise the following expressions. (vii) 10 ๐‘Ž^2 โ€“ 15 ๐‘^2 + 20 ๐‘^2 Now, 10๐‘Ž^2= 10 ร— ๐‘Ž^2 = 2 ร— 5 ร— ๐‘Ž^2 = 2 ร— 5 ร— a ร— a 15๐‘^2 = 15 ร— ๐‘^2 = 3 ร— 5 ร— ๐‘^2 = 2 ร— 5 ร— b ร— b 20๐‘^2 = 20 ร— ๐‘^2 = 2 ร— 2 ร— 5 ร— ๐‘^2 = 2 ร— 2 ร— 5 ร— c ร— c So, 5 is the common factor. 10๐‘Ž^2 โ€“ 15๐‘^2 + 20๐‘^2 = (2 ร— 5 ร— a ร— a) โˆ’ (3 ร— 5 ร— b ร— b) + (2 ร— 2 ร— 5 ร— c ร— c) Taking 5 common = 5 ร— ((2 ร— a ร— a) โˆ’ (3 ร— b ร— b) + (2 ร— 2 ร— c ร— c)) = 5 ร— (2๐‘Ž^2 โˆ’ 3๐‘^2 + 4๐‘^2) = 5 (2๐’‚^๐Ÿ โˆ’ 3๐’ƒ^๐Ÿ + 4๐’„^๐Ÿ) Ex 14.1, 2 (Method 2) Factorise the following expressions. (vii) 10 ๐‘Ž^2 โ€“ 15 ๐‘^2 + 20 ๐‘^2 10 ๐‘Ž^2 โ€“ 15 ๐‘^2 + 20 ๐‘^2 = (5 ร— 2) ๐‘Ž^2 โˆ’ (5 ร— 3 ) ๐‘^2 + (5 ร— 4) ๐‘^2 Taking 5 common, = 5 (2๐’‚^๐Ÿ โˆ’ 3๐’ƒ^๐Ÿ + 4๐’„^๐Ÿ)

About the Author

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.