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  1. Chapter 14 Class 8 Factorisation
  2. Serial order wise

Transcript

Ex 14.1, 2 (Method 1) Factorise the following expressions. (viii) โ€“ 4๐‘Ž^2 + 4 ab โ€“ 4 ca Now, โ€“ 4๐‘Ž^2 = โˆ’4 ร— ๐‘Ž^2 = โˆ’1 ร— 4 ร— ๐‘Ž^2 = โˆ’1 ร— 2 ร— 2 ร— ๐‘Ž^2 = โˆ’1 ร— 2 ร— 2 ร— a ร— a 4ab = 4 ร— a ร— b = 2 ร— 2 ร— a ร— b 4ca = 4 ร— c ร— a = 2 ร— 2 ร— c ร— a So, 2, 2 and a are the common factors. โ€“ 4๐‘Ž^2 + 4ab โˆ’4ca = (โˆ’1 ร— 2 ร— 2 ร— a ร— a) + (2 ร— 2 ร— a ร— b) โˆ’ (2 ร— 2 ร— c ร— a) Taking 2 ร— 2 ร— a common, = 2 ร— 2 ร— a ร— ((โˆ’1 ร— a) + b โˆ’ c) = 4a (โˆ’a + b โˆ’ c) Ex 14.1, 2 (Method 2) Factorise the following expressions. (viii) โ€“ 4๐‘Ž^2 + 4 ab โ€“ 4 ca โ€“ 4๐‘Ž^2 + 4 ab โ€“ 4 ca Taking 4 common, = 4 (โ€“๐‘Ž^2 + ab โˆ’ ca) = 4 ((โˆ’a ร— a) + (a ร— b) โˆ’ (c ร— a)) Taking a common, = 4a (โˆ’a + b โˆ’ c)

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.