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Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


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Ex 12.1, 2 (Method 1) Factorise the following expressions. (viii) – 4𝑎^2 + 4 ab – 4 ca– 4𝑎^2 + 4 ab – 4 ca Taking 4 common, = 4 (–𝑎^2 + ab − ca) = 4 ((−a × a) + (a × b) − (c × a)) Taking a common, = 4a (−a + b − c) Ex 12.1, 2 (Method 2) Factorise the following expressions. (viii) – 4𝑎^2 + 4 ab – 4 caNow, – 4𝒂^𝟐 = −4 × 𝑎^2 = −1 × 4 × 𝑎^2 = −1 × 2 × 2 × 𝑎^2 = −1 × 2 × 2 × a × a 4ab = 4 × a × b = 2 × 2 × a × b 4ca = 4 × c × a = 2 × 2 × c × a So, 2, 2 and a are the common factors. – 4𝑎^2 + 4ab −4ca = (−1 × 2 × 2 × a × a) + (2 × 2 × a × b) − (2 × 2 × c × a) Taking 2 × 2 × a common, = 2 × 2 × a × ((−1 × a) + b − c) = 4a (−a + b − c)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.