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 Example 19 - In an experiment, solution of hydrochloric acid - Examples

Example 19 - Chapter 6 Class 11 Linear Inequalities - Part 2
Example 19 - Chapter 6 Class 11 Linear Inequalities - Part 3 Example 19 - Chapter 6 Class 11 Linear Inequalities - Part 4


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Example 19 (Method 1) In an experiment, a solution of hydrochloric acid is to be kept between 30° and 35° Celsius. What is the range of temperature in degree Fahrenheit if conversion formula is given by C = 5﷮9﷯ (F – 32), where C and F represent temperature in degree F = 9﷮5﷯ C + 32 Given that the solution is to be kept between 30°C and 35°C, Hence, 86 < F < 95 Hence when value of C is between 30°C and 35°C, value of F is between 86 °F & 95 °F Example 19 (Method 2) In an experiment, a solution of hydrochloric acid is to be kept between 30° and 35° Celsius. What is the range of temperature in degree Fahrenheit if conversion formula is given by C = 5﷮9﷯ (F – 32), where C and F represent temperature in degree Given F = 9﷮5﷯ C + 32 F – 32 = 9﷮5﷯ C 9﷮5﷯ C = F – 32 C = 5﷮9﷯ (F – 32) Given that the solution is to be kept between 30°C and 35°C, 30 < C < 35 30 < 5﷮9﷯ (F – 32) < 35, Multiplying 9﷮5﷯ both sides (Eliminating 5﷮9﷯) 9﷮5﷯ × (30) < 5﷮9﷯ (F – 32) × 9﷮5﷯ < 9﷮5﷯ × (35) 9 × 6 < F – 32 < 9 × 7 54 < F – 32 < 63 Adding 32 both sides (Eliminating 32) 54 + 32 < F – 32 + 32 < 63 + 32 86 < F < 95 Hence when value of C is between 30°C and 35°C, value of F is between 86 °F & 95 °F

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.