Example 12 - Chapter 6 Class 11 Linear Inequalities (Term 2)
Last updated at Dec. 8, 2016 by Teachoo
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Chapter 6 Class 11 Linear Inequalities (Term 2)
Serial order wise
- Ex 6.1
- Ex 6.2
- Ex 6.3
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Transcript
Example 12 Solve the following system of linear inequalities graphically. x + y ≥ 5 , x – y ≤ 3 First we solve x + y ≥ 5 Lets first draw graph of x + y = 5 Drawing graph Checking for (0,0) Putting x = 0, y = 0 x + y ≥ 5 0 + 0 ≥ 5 0 ≥ 5 which is false Hence origin does not lie in plane x + y ≥ 5. So, we shade the right side of line Now we solve x – y ≤ 3 Lets first draw graph of x – y = 3 Drawing graph Checking for (0,0) Putting x = 0, y = 0 x – y ≤ 3 0 – 0 ≤ 3 0 ≤ 3 which is true Hence origin lies in plane x + y ≥ 5. So, we shade left side of line Hence the shaded region is the solution of the given inequality
