# Example 13 - Chapter 6 Class 11 Linear Inequalities

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Example 13 Solve the following system of inequalities graphically: 5x + 4y 40, x 2, y 3 First we solve 5x + 4y 40 Lets first draw graph of 5x + 4y = 40 Drawing graph Checking for (0,0) 5x + 4y 40 Putting x = 0, y = 0 5(0) + 4(0) 40 0 40 which is true Hence origin lies in plane 5x + 4y 40 So, we shade left side of line Also, y 3 So, for all values of x , y = 3 Also, x 2 So, for all values of y , x = 2 Hence the shaded region represents the given inequality

Chapter 6 Class 11 Linear Inequalities

Serial order wise

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.