Example 8 - Chapter 6 Class 11 Linear Inequalities
Last updated at Feb. 17, 2020 by Teachoo
Last updated at Feb. 17, 2020 by Teachoo
Transcript
Example 8 Find all pairs of consecutive odd natural numbers, both of which are larger than 10, such that their sum is less than 40. Let the smaller odd natural number be x Since the larger integer is consecutive odd, it will be x + 2 Given that, Both integers are larger than 10 i.e. x > 10 Since x > 10 & x > 8 x > 10 & x + 2 > 10 x > 10 – 2 x > 8 Sum of the numbers is less than 40 ∴ x + (x + 2) < 40 2x + 2 < 40 2x < 40 – 2 2x < 38 x < 19 Hence, x > 10 & x < 19 Natural numbers greater than 10 but less than 19 are 11, 12, 13, 14, 15, 16, 17, 18 Odd natural numbers are 11,13,15,17 Hence x = 11, 13, 15, 17 Hence, finding the possible pairs as follows. Possible pairs are (11, 13) , (13, 15) , (15, 17), (17, 19)
Examples
Example 2 Important
Example 3
Example 4 Important
Example 5
Example 6
Example 7
Example 8 Important You are here
Example 9
Example 10 Important
Example 11 Important
Example 12
Example 13 Important
Example 14
Example 15
Example 16 Important
Example 17
Example 18 Important
Example 19
Example 20 Important
Examples
About the Author