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Last updated at Feb. 17, 2020 by Teachoo

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Example 8 Find all pairs of consecutive odd natural numbers, both of which are larger than 10, such that their sum is less than 40. Let the smaller odd natural number be x Since the larger integer is consecutive odd, it will be x + 2 Given that, Both integers are larger than 10 i.e. x > 10 Since x > 10 & x > 8 x > 10 & x + 2 > 10 x > 10 – 2 x > 8 Sum of the numbers is less than 40 ∴ x + (x + 2) < 40 2x + 2 < 40 2x < 40 – 2 2x < 38 x < 19 Hence, x > 10 & x < 19 Natural numbers greater than 10 but less than 19 are 11, 12, 13, 14, 15, 16, 17, 18 Odd natural numbers are 11,13,15,17 Hence x = 11, 13, 15, 17 Hence, finding the possible pairs as follows. Possible pairs are (11, 13) , (13, 15) , (15, 17), (17, 19)

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Chapter 6 Class 11 Linear Inequalities

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.