
Get live Maths 1-on-1 Classs - Class 6 to 12
Examples
Example 2 Important
Example 3
Example 4 Important
Example 5
Example 6
Example 7
Example 8 Important You are here
Example 9 Deleted for CBSE Board 2023 Exams
Example 10 Important Deleted for CBSE Board 2023 Exams
Example 11 Important Deleted for CBSE Board 2023 Exams
Example 12 Deleted for CBSE Board 2023 Exams
Example 13 Important Deleted for CBSE Board 2023 Exams
Example 14 Deleted for CBSE Board 2023 Exams
Example 15 Deleted for CBSE Board 2023 Exams
Example 16 Important
Example 17
Example 18 Important
Example 19
Example 20 Important
Examples
Last updated at March 16, 2023 by Teachoo
Example 8 Find all pairs of consecutive odd natural numbers, both of which are larger than 10, such that their sum is less than 40. Let the smaller odd natural number be x Since the larger integer is consecutive odd, it will be x + 2 Given that, Both integers are larger than 10 i.e. x > 10 Since x > 10 & x > 8 x > 10 & x + 2 > 10 x > 10 – 2 x > 8 Sum of the numbers is less than 40 ∴ x + (x + 2) < 40 2x + 2 < 40 2x < 40 – 2 2x < 38 x < 19 Hence, x > 10 & x < 19 Natural numbers greater than 10 but less than 19 are 11, 12, 13, 14, 15, 16, 17, 18 Odd natural numbers are 11,13,15,17 Hence x = 11, 13, 15, 17 Hence, finding the possible pairs as follows. Possible pairs are (11, 13) , (13, 15) , (15, 17), (17, 19)