Example 2 Solve 5x – 3 < 3x +1 when (i) x is an integer, 5x – 3 < 3x + 1 5x – 3x < 1 +3 2x < 4 x < ﷐4﷮2﷯ x < 2 Since x is an integer (……,-3, -2, -1, 0, 1, 2, 3….) We need to find values of x which is less than 2 i.e. x can be ……-3,-2,-1,0,1 = {……. –3, –2, –1, 0, 1} (ii) x is a real number Now, x < 2 Since x is a real number which is less than 2 Thus x ∈ (–𕔴, 2).

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