Example 4 - Chapter 6 Class 11 Linear Inequalities (Term 2)
Last updated at Feb. 17, 2020 by Teachoo
Examples
Example 1
Example 2 Important
Example 3
Example 4 Important You are here
Example 5
Example 6
Example 7
Example 8 Important
Example 9
Example 10 Important
Example 11 Important
Example 12
Example 13 Important
Example 14
Example 15
Example 16 Important
Example 17
Example 18 Important
Example 19
Example 20 Important
Chapter 6 Class 11 Linear Inequalities (Term 2)
Serial order wise
- Ex 6.1
- Ex 6.2
- Ex 6.3
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Examples
- Miscellaneous
Transcript
Example 4 Solve (5 β 2π₯)/3 β€ π₯/6 β 5. (5 β 2π₯)/3 β€ π₯/6 β 5 (5 β 2π₯)/3 β€ (π₯ β 30)/6 6 Γ (5 β 2π₯)/3 β€ x β 30 2(5 β 2x) β€ x β 30. 10 β 4x β€ x β 30 β 4x β x β€ β 30 β 10 β 5x β€ β 40 β x β€ (β40)/( 5) β x β€ β8 Since x is negative, we multiply both sides by β1 & change the signs (β 1) Γ (βx) β₯ (β 1) Γ (β8) x β₯ 8 Hence, x is a real number greater than or equal to 8 Hence, x β [8, β) is the solution
