Example 4 - Chapter 6 Class 11 Linear Inequalities (Term 2)
Last updated at Feb. 17, 2020 by Teachoo
Transcript
Example 4 Solve (5 โ 2๐ฅ)/3 โค ๐ฅ/6 โ 5. (5 โ 2๐ฅ)/3 โค ๐ฅ/6 โ 5 (5 โ 2๐ฅ)/3 โค (๐ฅ โ 30)/6 6 ร (5 โ 2๐ฅ)/3 โค x โ 30 2(5 โ 2x) โค x โ 30. 10 โ 4x โค x โ 30 โ 4x โ x โค โ 30 โ 10 โ 5x โค โ 40 โ x โค (โ40)/( 5) โ x โค โ8 Since x is negative, we multiply both sides by โ1 & change the signs (โ 1) ร (โx) โฅ (โ 1) ร (โ8) x โฅ 8 Hence, x is a real number greater than or equal to 8 Hence, x โ [8, โ) is the solution
Examples
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Example 2 Important
Example 3
Example 4 Important You are here
Example 5
Example 6
Example 7
Example 8 Important
Example 9
Example 10 Important
Example 11 Important
Example 12
Example 13 Important
Example 14
Example 15
Example 16 Important
Example 17
Example 18 Important
Example 19
Example 20 Important
Chapter 6 Class 11 Linear Inequalities (Term 2)
Serial order wise
- Ex 6.1
- Ex 6.2
- Ex 6.3
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Examples
- Miscellaneous
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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.