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Example 4 - Solve 5 - 2x /3 <= x/6 - 5 - Chapter 6 Class 11

Example 4 - Chapter 6 Class 11 Linear Inequalities - Part 2


Transcript

Example 4 Solve (5 βˆ’ 2π‘₯)/3 ≀ π‘₯/6 βˆ’ 5. (5 βˆ’ 2π‘₯)/3 ≀ π‘₯/6 βˆ’ 5 (5 βˆ’ 2π‘₯)/3 ≀ (π‘₯ βˆ’ 30)/6 6 Γ— (5 βˆ’ 2π‘₯)/3 ≀ x – 30 2(5 – 2x) ≀ x – 30. 10 – 4x ≀ x – 30 – 4x – x ≀ – 30 – 10 – 5x ≀ – 40 – x ≀ (βˆ’40)/( 5) – x ≀ βˆ’8 Since x is negative, we multiply both sides by βˆ’1 & change the signs (– 1) Γ— (–x) β‰₯ (– 1) Γ— (–8) x β‰₯ 8 Hence, x is a real number greater than or equal to 8 Hence, x ∈ [8, ∞) is the solution

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.