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Example 4 - Solve 5 - 2x /3 <= x/6 - 5 - Chapter 6 Class 11

Example 4 - Chapter 6 Class 11 Linear Inequalities - Part 2


Transcript

Example 4 Solve (5 βˆ’ 2π‘₯)/3 ≀ π‘₯/6 βˆ’ 5. (5 βˆ’ 2π‘₯)/3 ≀ π‘₯/6 βˆ’ 5 (5 βˆ’ 2π‘₯)/3 ≀ (π‘₯ βˆ’ 30)/6 6 Γ— (5 βˆ’ 2π‘₯)/3 ≀ x – 30 2(5 – 2x) ≀ x – 30. 10 – 4x ≀ x – 30 – 4x – x ≀ – 30 – 10 – 5x ≀ – 40 – x ≀ (βˆ’40)/( 5) – x ≀ βˆ’8 Since x is negative, we multiply both sides by βˆ’1 & change the signs (– 1) Γ— (–x) β‰₯ (– 1) Γ— (–8) x β‰₯ 8 Hence, x is a real number greater than or equal to 8 Hence, x ∈ [8, ∞) is the solution

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.