Example 4 - Chapter 6 Class 11 Linear Inequalities
Last updated at May 29, 2018 by Teachoo
Transcript
Example 4 Solve 5 2 3 6 5. 5 2 3 6 5 5 2 3 30 6 6 5 2 3 x 30 2(5 2x) x 30. 10 4x x 30 4x x 30 10 5x 40 x 40 5 x 8 Since x is negative, we multiply both sides by -1 & change the signs ( 1) ( x) ( 1) ( 8) x 8 Hence, x is a real number greater than or equal to 8 Hence, x [8, ) is the solution
Chapter 6 Class 11 Linear Inequalities
Serial order wise
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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.