Example 17 - Chapter 6 Class 11 Linear Inequalities (Term 2)
Last updated at Dec. 8, 2016 by Teachoo
Transcript
Example 17 Solve 5 5 3 2 8. 5 5 3 2 8 Multiplying 2 all sides (Eliminating 2) 5 2 5 3x 8 2 10 5 3x 16 Subtracting 5 all sides (Eliminating 5) 10 5 5 3x 5 16 5 10 5 5 3x 5 16 5 15 3x 11 Dividing 3 all sides (Eliminating 3) 15 3 3 3 11 3 -5 11 3 Since x is negative, we multiply both sides by -1 & change the signs ( 1) (-5) ( 1) ( x) ( 1) ( 11 3 ) 5 x 11 3 11 3 x 5 Thus, x is a real number which is less than or equal to 5 and greater than or equal to 11 3 Hence, x , 5 is the solution
Examples
Example 1
Example 2 Important
Example 3
Example 4 Important
Example 5
Example 6
Example 7
Example 8 Important
Example 9
Example 10 Important
Example 11 Important
Example 12
Example 13 Important
Example 14
Example 15
Example 16 Important
Example 17 You are here
Example 18 Important
Example 19
Example 20 Important
Chapter 6 Class 11 Linear Inequalities (Term 2)
Serial order wise
- Ex 6.1
- Ex 6.2
- Ex 6.3
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Examples
- Miscellaneous
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.