Example 10 Solve 5 5 3 2 8. 5 5 3 2 8 Multiplying 2 all sides (Eliminating 2) 5 2 5 3x 8 2 10 5 3x 16 Subtracting 5 all sides (Eliminating 5) 10 5 5 3x 5 16 5 10 5 5 3x 5 16 5 15 3x 11 Dividing 3 all sides (Eliminating 3) 15 3 3 3 11 3 -5 11 3 Since x is negative, we multiply both sides by -1 & change the signs ( 1) (-5) ( 1) ( x) ( 1) ( 11 3 ) 5 x 11 3 11 3 x 5 Thus, x is a real number which is less than or equal to 5 and greater than or equal to 11 3 Hence, x , 5 is the solution

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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