![Example 14 - Chapter 6 Class 11 Linear Inequalities - Part 2](https://d1avenlh0i1xmr.cloudfront.net/dc9cf3a1-b084-4fed-8eab-56158dca8731/slide5.jpg)
![Example 14 - Chapter 6 Class 11 Linear Inequalities - Part 3](https://d1avenlh0i1xmr.cloudfront.net/cadb4da1-98cc-40ac-9c81-09348b0e5e63/slide6.jpg)
Examples
Last updated at April 16, 2024 by Teachoo
Question 6 Solve the following system of inequalities : 8x + 3y ≤ 100 , x ≥ 0 , y ≥ 0 First we solve 8x + 3y ≥ 100 Lets first draw graph of 8x + 3y = 100 Drawing graph Checking for (0,0) Putting x = 0, y = 0 8x + 3y ≤ 100 8(0) + 3(0) ≤ 100 0 ≤ 100 which is true So, we shade left side of line Hence origin lies in plane 8x + 3y ≤ 100 Also x ≥ 0 & y ≥ 0 So, our shaded region will lie in first quadrant. Hence the shaded region represents the given inequality