Finding equation of tangent/normal when point and curve is given
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Finding equation of tangent/normal when point and curve is given
Last updated at April 16, 2024 by Teachoo
Misc 23 The normal to the curve π₯^2=4π¦ passing (1, 2) is (π΄) π₯ + π¦ = 3 (π΅) π₯ β π¦ = 3 (πΆ) π₯ + π¦ = 1 (π·) π₯ β π¦ = 1Since (1, 2) lies on normal, it will satisfy its equation Option 1: π+π=π Putting π₯=1 & π¦=2 in equation 1 +2=3 3=3 This is true So, it is the equation of Normal Option 2: πβπ=π Putting π₯=1 & π¦=2 in equation 1 β2=3 β1=3 This is false So, it is not equation of Normal Option 3: π+π=π Putting π₯=1 & π¦=2 in equation 1 +2=1 3=1 This is false So, it is not equation of Normal Option 4: πβπ=π Putting π₯=1 & π¦=2 in equation 1 β1=1 0=1 This is false So, it is not equation of Normal Hence, Correct Answer is (A)