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Last updated at Feb. 15, 2020 by Teachoo

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Ex 6.1, 25 The longest side of a triangle is 3 times the shortest side and the third side is 2 cm shorter than the longest side. If the perimeter of the triangle is at least 61 cm, find the minimum length of the shortest side. Let the length of the shortest side be x cm. So, length of longest side = 3 times shorter side = 3x & Length of the third side = (3x – 2) cm Now, Perimeter = Sum of three sides = x + 3x + (3x – 2) = x + 3x + 3x – 2 = 7x – 2 Given that, perimeter of the triangle is at least 61 cm, i.e. Perimeter ≥ 61 7x – 2 ≥ 61 7x ≥ 61 + 2 7x ≥ 63 𝑥 ≥ 63/7 x ≥ 9 ∴ Minimum value of x is 9 Thus, the minimum length of the shortest side is 9 cm.

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Chapter 6 Class 11 Linear Inequalities

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.