Ex 6.1, 5 - Chapter 6 Class 11 Linear Inequalities (Term 2)
Last updated at Dec. 8, 2016 by Teachoo
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Ex 6.1, 5 Solve the given inequality for real x: 4x + 3 < 5x + 7 4x + 3 < 5x + 7 4x 5x < 7 3 x < 4 Since x is negative, we multiply both sides by -1 & change the signs -1 ( x) > (-1) 4 x > 4 Since x is a real number greater than 4 Thus x ( 4, )