Ex 6.1, 5 - Class 11
Last updated at Dec. 8, 2016 by Teachoo
Transcript
Ex 6.1, 5 Solve the given inequality for real x: 4x + 3 < 5x + 7 4x + 3 < 5x + 7 4x – 5x < 7 – 3 –x < 4 Since x is negative, we multiply both sides by -1 & change the signs -1 × (–x) > (-1) × 4 x > – 4 Since x is a real number greater than – 4 Thus x ∈ (–4, )
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Chapter 6 Class 11 Linear Inequalities
Serial order wise
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.
