Ex 5.1, 12 - Chapter 5 Class 11 Linear Inequalities

Last updated at Dec. 16, 2024 by

Slide18.JPG

Slide19.JPG

Share on WhatsApp

Transcript

Ex 5.1, 12 Solve the given inequality for real x: 1 2 3 5 +4 1 3 (x 6) 1 2 3 5 +4 1 3 (x 6) 3 3 5 +4 2 (x 6) 3 3 5 + 3 4 2x 2 6 9 5 + 12 2x 12 9 5 2x 12 12 9 5(2 ) 5 24 9 10 5 24 5 24 24 5 120 Since x is negative, we multiply both sides by -1 & change the signs ( 1) ( x) ( 1) ( 120) x 120 Hence, x is a real number which is less than or equal to 120 Hence, x ( 120] is the solution

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo