Ex 6.1, 16 - Chapter 6 Class 11 Linear Inequalities

Last updated at May 29, 2018 by Teachoo

Ex 6.1, 16 - Solve: (2x - 1)/3 >= (3x - 2)/4 - (2 - x)/5 - Solving inequality (one side)

Transcript

Ex 6.1, 16 Solve the given inequality for real x: ((2𝑥 − 1))/3 ≥ ((3𝑥 − 2))/4−((2 − 𝑥))/5 ((2𝑥 − 1))/3 ≥ ((3𝑥 − 2))/4 −((2 − 𝑥))/5 ((2𝑥 − 1))/3 ≥ (5(3𝑥 − 2) − 4(2 − 𝑥))/(4(5)) ((2𝑥 − 1))/3 ≥ (15𝑥 − 10 − 8 + 4𝑥)/20 ((2𝑥 − 1))/3 ≥ (15𝑥 + 4𝑥 − 10 − 8 )/20 ((2𝑥 − 1))/3 ≥ (19𝑥 − 18 )/20 20 (2x – 1) ≥ 3 (19x – 18) 40x – 20 ≥ 57x – 54 40x – 57x ≥ – 54 + 20 –17x ≥ – 34 –x ≥ (−34)/( 17) –x ≥ −2 Since x is negative, we multiply both sides by -1 & change the signs (– 1) × (–x) ≤ (–1) × (–2) x ≤ 2 Hence, x is a real number which is less than or equal to 2 Hence, x ∈ (–∞, 2] is the solution

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Chapter 6 Class 11 Linear Inequalities

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.