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Ex 6.1, 15 - Solve: x/4 < (5x - 2)/3 - (7x - 3)5 NCERT - Solving inequality  (one side)

Ex 6.1,  15 - Chapter 6 Class 11 Linear Inequalities - Part 2

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Transcript

Ex 5.1, 15 Solve the given inequality for real x: ﷐𝑥﷮4﷯ < ﷐(5𝑥 − 2)﷮3﷯ −﷐(7𝑥 − 3)﷮5﷯ ﷐𝑥﷮4﷯ < ﷐(5𝑥 − 2)﷮3﷯ −﷐(7𝑥 − 3)﷮5﷯ ﷐𝑥﷮4﷯ < ﷐5﷐5𝑥 − 2﷯ −3 (7𝑥 − 3)﷮3(5)﷯ ﷐𝑥﷮4﷯ < ﷐25𝑥 −10 − 21𝑥 + 9﷮15﷯ ﷐𝑥﷮4﷯ < ﷐25𝑥 − 21𝑥 + 9 −10﷮15﷯ ﷐𝑥﷮4﷯ < ﷐4𝑥 − 1﷮15﷯ 15x < 4 (4x – 1) 15x < 16x – 4 15x – 16x < − 4 –x < −4 Since x is negative, we multiply both sides by -1 & change the signs (– 1) × (–x) > (– 1) × (−4) x > 4 Hence, x is a real number which is greater than 4 Hence, x ∈ (4,𕔴 is the solution

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.