1. Chapter 6 Class 11 Linear Inequalities (Term 2)
  2. Serial order wise
  3. Ex 6.1

Ex 6.1, 15 - Chapter 6 Class 11 Linear Inequalities (Term 2)

Last updated at May 29, 2018 by

Ex 6.1, 15 - Solve: x/4 < (5x - 2)/3 - (7x - 3)5 NCERT - Solving inequality (one side)

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Ex 6.1, 15 - Chapter 6 Class 11 Linear Inequalities - Part 2

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  1. Chapter 6 Class 11 Linear Inequalities (Term 2)
  2. Serial order wise

    3. Ex 6.1

    Ex 6.2 →

Transcript

Ex 6.1, 15 Solve the given inequality for real x: ﷐𝑥﷮4﷯ < ﷐(5𝑥 − 2)﷮3﷯ −﷐(7𝑥 − 3)﷮5﷯ ﷐𝑥﷮4﷯ < ﷐(5𝑥 − 2)﷮3﷯ −﷐(7𝑥 − 3)﷮5﷯ ﷐𝑥﷮4﷯ < ﷐5﷐5𝑥 − 2﷯ −3 (7𝑥 − 3)﷮3(5)﷯ ﷐𝑥﷮4﷯ < ﷐25𝑥 −10 − 21𝑥 + 9﷮15﷯ ﷐𝑥﷮4﷯ < ﷐25𝑥 − 21𝑥 + 9 −10﷮15﷯ ﷐𝑥﷮4﷯ < ﷐4𝑥 − 1﷮15﷯ 15x < 4 (4x – 1) 15x < 16x – 4 15x – 16x < − 4 –x < −4 Since x is negative, we multiply both sides by -1 & change the signs (– 1) × (–x) > (– 1) × (−4) x > 4 Hence, x is a real number which is greater than 4 Hence, x ∈ (4,𕔴 is the solution

Chapter 6 Class 11 Linear Inequalities (Term 2)
Serial order wise

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