Ex 6.1, 10 - Solve: x/3 > x/2 + 1 - Chapter 6 Linear Inequalities

Ex 6.1,  10 - Chapter 6 Class 11 Linear Inequalities - Part 2

  1. Chapter 6 Class 11 Linear Inequalities
  2. Serial order wise

Transcript

Ex 6.1, 10 Solve the given inequality for real x: ๐‘ฅ/3 > ๐‘ฅ/2 + 1 ๐‘ฅ/3 > ๐‘ฅ/2 + 1 ๐‘ฅ/3 โˆ’๐‘ฅ/2 > 1 (2๐‘ฅ โˆ’ 3๐‘ฅ)/6 > 1 (โˆ’๐‘ฅ)/6 > 1 โˆ’x > 6 Since x is negative, we multiply both sides by -1 & change the signs (โ€“ 1) ร— (โ€“x) < (โ€“ 1) ร— (6) x < โ€“6 C Hence x is a real number which is less than โ€“6 Thus , solution is (โ€“โˆž, โ€“6).

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.