Ex 5.1, 3 - Chapter 5 Class 11 Linear Inequalities
Last updated at April 16, 2024 by Teachoo
Ex 5.1
Ex 5.1, 1
Ex 5.1, 2
Ex 5.1, 3 You are here
Ex 5.1, 4 Important
Ex 5.1, 5
Ex 5.1, 6 Important
Ex 5.1, 7
Ex 5.1, 8 Important
Ex 5.1, 9
Ex 5.1, 10 Important
Ex 5.1, 11 Important
Ex 5.1, 12
Ex 5.1, 13
Ex 5.1, 14
Ex 5.1, 15
Ex 5.1, 16 Important
Ex 5.1, 17 Important
Ex 5.1, 18
Ex 5.1, 19
Ex 5.1, 20 Important
Ex 5.1, 21
Ex 5.1, 22 Important
Ex 5.1, 23 Important
Ex 5.1, 24
Ex 5.1, 25 Important
Ex 5.1, 26
Transcript
Ex 5.1, 3 Solve 5x 3 < 7, when x is an integer 5x 3 < 7 5x < 7 + 3 5x < 10 x < 10 5 x < 2 Since x is an integer ( ,-3,-2,-1,0,1,2,3 .) We need to find values of x which is less than 2 i.e. x can be -3,-2,-1,0,1 = { 3, 2, 1, 0, 1} (ii) x is a real number Now, x < 2 Since x is a real number which is less than 2 Thus x ( 2).
