Ex 6.1, 4 - Solve 3x + 8 > 2, x is an integer - Class 11

Ex 6.1,  4 - Chapter 6 Class 11 Linear Inequalities - Part 2

  1. Chapter 6 Class 11 Linear Inequalities (Term 2)
  2. Serial order wise

Transcript

Ex 6.1, 4 Solve 3x + 8 > 2, when x is an integer 3x + 8 > 2 3x > 2 โ€“ 8 3x > โ€“6 ๐‘ฅ > (โˆ’6)/3 ๐‘ฅ > โˆ’2 Since x is an integer (โ€ฆโ€ฆ,โˆ’3, โˆ’2, โˆ’1, 0, 1, 2, 3โ€ฆ.) We need to find values of x which is greater than -2 i.e. x can be -1, 0, 1, 2, 3, 4,โ€ฆโ€ฆ.. = {โ€“1, 0, 1, 2, 3, 4,โ€ฆโ€ฆ} Integers: โ€ฆ..,โ€“2, โ€“1, 0, 1, 2, 3,โ€ฆ. Ex 6.1, 4 Solve 3x + 8 > 2, when (ii) x is a real number Now, x > โˆ’2 Since x is a real number which is greater than โ€“2 Thus x โˆˆ (โ€“2, โˆž)

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.