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Ex 6.1, 4 - Solve 3x + 8 > 2, x is an integer - Class 11

Ex 6.1,  4 - Chapter 6 Class 11 Linear Inequalities - Part 2

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Ex 6.1, 4 Solve 3x + 8 > 2, when x is an integer 3x + 8 > 2 3x > 2 – 8 3x > –6 𝑥 > (−6)/3 𝑥 > −2 Since x is an integer (……,−3, −2, −1, 0, 1, 2, 3….) We need to find values of x which is greater than -2 i.e. x can be -1, 0, 1, 2, 3, 4,…….. = {–1, 0, 1, 2, 3, 4,……} Integers: …..,–2, –1, 0, 1, 2, 3,…. Ex 6.1, 4 Solve 3x + 8 > 2, when (ii) x is a real number Now, x > −2 Since x is a real number which is greater than –2 Thus x ∈ (–2, ∞)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.