Ex 6.1, 4 - Solve 3x + 8 > 2, x is an integer - Class 11 - Ex 6.1

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  1. Chapter 6 Class 11 Linear Inequalities
  2. Serial order wise

Transcript

Ex 6.1, 4 Solve 3x + 8 > 2, when x is an integer 3x + 8 > 2 3x > 2 – 8 3x > –6 𝑥 > ﷐−6﷮3﷯ 𝑥 > -2 Since x is an integer (……,-3,-2,-1,0,1,2,3….) We need to find values of x which is greater than -2 i.e. x can be -1,0,1,2,3,4,…….. = {–1, 0, 1, 2, 3, 4,……} (ii) x is a real number Now, x > -2 Since x is a real number which is greater than –2 Thus x ∈ (–2, 𕔴

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