Check sibling questions

Ex 6.1, 14 - Solve: 37 ­- (3x + 5) >= 9x - 8(x - 3) - Solving inequality  (one side)


Transcript

Ex 6.1, 14 Solve the given inequality for real x: 37 ­– (3x + 5) ≥ 9x – 8(x – 3) 37 ­– (3x + 5) ≥ 9x – 8(x – 3) 37 – 3x – 5 ≥ 9x – 8x + 24 32 – 3x ≥ x + 24 –3x – x ≥ 24 – 32 –4x ≥ – 8 –x ≥ ﷐−8﷮ 4﷯ –x ≥ −2 Since x is negative, we multiply both sides by -1 & change the signs (– 1) × (–x) ≤ (– 1) × (–2) x ≤ 2 Since x is a real number which is less than or equal to 2 Hence, x ∈ (–𕔴2] is the solution

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.