Example 11 - Find intervals in which f(x) is strictly - Examples - Examples

part 2 - Example 11 - Examples - Serial order wise - Chapter 6 Class 12 Application of Derivatives
part 3 - Example 11 - Examples - Serial order wise - Chapter 6 Class 12 Application of Derivatives

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Example 11 Find the intervals in which the function f given by f (š‘„)=4š‘„3āˆ’6š‘„2 –72š‘„+30 is (a) strictly increasing (b) strictly decreasing. f (š‘„)=4š‘„3āˆ’6š‘„2 –72š‘„+30 Calculating f’(x) f (š‘„)=4š‘„3āˆ’6š‘„2–72š‘„+30 š‘“ā€²(š‘„)=12š‘„2āˆ’12š‘„ –72š‘„ š‘“ā€²(š‘„) =12(š‘„2āˆ’š‘„ – 6) š‘“ā€²(š‘„) =12(š‘„2āˆ’3š‘„+2š‘„ –6) š‘“ā€²(š‘„) = 12(š‘„(š‘„ āˆ’ 3) + 2(š‘„ āˆ’ 3)) š’‡ā€²(š’™)=šŸšŸ(š’™+šŸ)(š’™ ā€“šŸ‘) Putting f’(x) = 0 12(š‘„+2)(š‘„ –3)=0 (š‘„+2)(š‘„ –3)=0 So, x = āˆ’2 and x = 3 Plotting points on number line Hence, f is strictly increasing in (āˆ’āˆž ,āˆ’šŸ) & (šŸ‘ ,āˆž) f is strictly decreasing in (āˆ’šŸ, šŸ‘)

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