Ex 6.2, 5 - Find intervals where f(x) = 2x^3 - 3x^2 - 36x + 7 is

Ex 6.2, 5 - Chapter 6 Class 12 Application of Derivatives - Part 2
Ex 6.2, 5 - Chapter 6 Class 12 Application of Derivatives - Part 3

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Ex 6.2, 5 Find the intervals in which the function f given by f (š‘„) = 2š‘„3 – 3š‘„2 – 36š‘„ + 7 is (a) strictly increasing (b) strictly decreasingf(š‘„) = 2š‘„3 – 3š‘„2 – 36š‘„ + 7 Calculating f’(š’™) f’(š‘„) = 6š‘„2 – 6š‘„ – 36 + 0 f’(š‘„) = 6 (š‘„2 – š‘„ – 6 ) f’(š‘„) = 6(š‘„^2 – 3š‘„ + 2š‘„ – 6) f’(š‘„) = 6(š‘„(š‘„ āˆ’ 3) + 2 (š‘„ āˆ’ 3)) f’(š’™) = 6(š’™ – 3) (š’™ + 2) Putting f’(x) = 0 6(š‘„+2)(š‘„ –3)=0 (š‘„+2)(š‘„ –3)=0 So, x = āˆ’2 and x = 3 Plotting points on number line Hence, f is strictly increasing in (āˆ’āˆž ,āˆ’šŸ) & (šŸ‘ ,āˆž) f is strictly decreasing in (āˆ’šŸ, šŸ‘)

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