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Ex 13.1
Ex 13.1, 2
Ex 13.1, 3 Important
Ex 13.1, 4
Ex 13.1, 5
Ex 13.1, 6 (i)
Ex 13.1, 6 (ii) Important
Ex 13.1, 6 (iii)
Ex 13.1, 7 (i)
Ex 13.1, 7 (ii)
Ex 13.1, 8
Ex 13.1, 9
Ex 13.1, 10 (a) Important
Ex 13.1, 10 (b) Important
Ex 13.1, 11
Ex 13.1, 12 Important
Ex 13.1, 13 Important
Ex 13.1, 14
Ex 13.1, 15
Ex 13.1, 16 (MCQ) Important
Ex 13.1, 17 (MCQ) Important You are here
Last updated at March 30, 2023 by Teachoo
Ex 13.1, 17 If A and B are events such that P(A|B) = P(B|A), then (A) A ⊂ B but A ≠ B (B) A = B (C) A ∩ B = φ (D) P(A) = P(B)Given P(A|B) = P(B|A) (𝑃(𝐴 ∩ 𝐵))/(𝑃(𝐴)) = (𝑃(𝐵 ∩ 𝐴))/(𝑃(𝐵)) (𝑃(𝐴 ∩ 𝐵))/(𝑃(𝐴)) = (𝑃(𝐴 ∩ 𝐵))/(𝑃(𝐵)) 1/(𝑃(𝐴)) = 1/(𝑃(𝐵)) ∴ "P(A) = P(B)" So, option (D) is correct (Since "P(B"∩"A)" = "P(A"∩"B) ")