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Ex 13.1, 4 - Chapter 13 Class 12 Probability
Last updated at Aug. 16, 2023 by Teachoo
Ex 13.1
Ex 13.1, 1
Ex 13.1, 2
Ex 13.1, 3 Important
Ex 13.1, 4 You are here
Ex 13.1, 5
Ex 13.1, 6 (i)
Ex 13.1, 6 (ii) Important
Ex 13.1, 6 (iii)
Ex 13.1, 7 (i)
Ex 13.1, 7 (ii)
Ex 13.1, 8
Ex 13.1, 9
Ex 13.1, 10 (a) Important
Ex 13.1, 10 (b) Important
Ex 13.1, 11
Ex 13.1, 12 Important
Ex 13.1, 13 Important
Ex 13.1, 14
Ex 13.1, 15
Ex 13.1, 16 (MCQ) Important
Ex 13.1, 17 (MCQ) Important
Chapter 13 Class 12 Probability
Serial order wise
Transcript
Ex 13.1, 4 Evaluate P(A ∪ B), if 2P(A) = P(B) = 5/13 and P(A|B) = 2/5Given, 2P(A) = P(B) = 5/13 Now, 2 P(A) = 5/13 ∴ P(A) = 1/2 × 5/13 = 𝟓/𝟐𝟔 And, P(B) = 5/13 Now, P(A|B) = (𝑃(𝐴 ∩ 𝐵))/(𝑃(𝐵)) 𝟐/𝟓 = (𝑷(𝑨 ∩ 𝑩))/(𝟓/𝟏𝟑) "P(A ∩ B)" = 2/5 × 5/13 "P(A ∩ B)" = 𝟐/𝟏𝟑 Also, "P(A"∪"B)" = P(A) + P(B) – "P(A ∩ B)" = 5/26 + 5/13 – 2/( 13) = 5/26 + 3/13 = 5/26 + 6/26 = 𝟏𝟏/𝟐𝟔 ∴ "P(A "∪" B)" = 𝟏𝟏/𝟐𝟔
