1. Chapter 13 Class 12 Probability (Term 2)
  2. Serial order wise
  3. Ex 13.1

Ex 13.1, 6 (iii) - Chapter 13 Class 12 Probability (Term 2)

Last updated at Aug. 24, 2021 by

Ex 13.1, 6 - Chapter 13 Class 12 Probability - Part 5

Ex 13.1, 6 - Chapter 13 Class 12 Probability - Part 6

  1. Chapter 13 Class 12 Probability (Term 2)
  2. Serial order wise

    3. Ex 13.1

    Ex 13.2 →

Transcript

Ex 13.1, 6 Determine P(E|F) A coin is tossed three times, where (iii) E : at most two tails , F : at least one tail Coin is tossed three times S = {HHH, HHT, THH, HTH, TTH, THT, HTT, TTT} E : at most two tails E = {HHH, HHT, HTH, THH, TTH, THT, HHT} P(E) = 7/8 F : at least one tail F = {HHT, HTH, THH, TTH THT, HTT, TTT} P(F) = 7/8 Also, E ∩ F = {HHT, HTH, THH, TTH, THT, HTT} P(E ∩ F) = 6/8 Now, P(E|F) = (𝑃(𝐸 ∩ 𝐹))/(𝑃(𝐹)) = (6/8 )/(7/8 ) = 6/8 × 8/7 = 6/7 ∴ P(E|F) = 𝟔/𝟕

Chapter 13 Class 12 Probability (Term 2)
Serial order wise

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