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Ex 13.1
Ex 13.1, 2
Ex 13.1, 3 Important
Ex 13.1, 4
Ex 13.1, 5
Ex 13.1, 6 (i)
Ex 13.1, 6 (ii) Important
Ex 13.1, 6 (iii)
Ex 13.1, 7 (i)
Ex 13.1, 7 (ii)
Ex 13.1, 8
Ex 13.1, 9
Ex 13.1, 10 (a) Important You are here
Ex 13.1, 10 (b) Important
Ex 13.1, 11
Ex 13.1, 12 Important
Ex 13.1, 13 Important
Ex 13.1, 14
Ex 13.1, 15
Ex 13.1, 16 (MCQ) Important
Ex 13.1, 17 (MCQ) Important
Last updated at March 22, 2023 by Teachoo
Ex 13.1, 10 A black and a red dice are rolled. (a) Find the conditional probability of obtaining a sum greater than 9, given that the black die resulted in a 5.A black and a red dice are rolled Let us take first numbers to have been appeared on the black die and the second numbers on the red die, in order. S = {(1, 1), ……….., (1, 6), (2, 1), ………, (2, 6), (3, 1), ………., (3, 6), (4, 1), ……...., (4, 6), (5, 1), …….., (5, 6), (6, 1), …..…., (6, 6)} We need to find the probability of obtaining a sum greater than 9, given that the black die resulted in 5 Let F : 5 appeared on the black die E: Sum of numbers greater than 9 We need to find P(E|F) Also, E ∩ F = {(5, 5), (5, 6)} So, P(E ∩ F) = 2/36 = 1/18 E = {(4, 6), (5, 5), (6, 4), (5, 6), (6, 5) , (6, 6)} P(E) = 6/36 F = {(5, 1), (5, 2), (5, 3), (5, 4), (5,5), (5,6)} P(F) = 6/36 Now, P(E|F) = (𝑃(𝐸 ∩ 𝐹))/(𝑃(𝐹)) = (2/36)/(6/36) = 2/6 = 𝟏/𝟑 ∴ Required probability is 1/3 ∴ Required probability is 1/9