1. Chapter 13 Class 12 Probability (Term 2)
  2. Serial order wise
  3. Ex 13.1

Ex 13.1, 6 (ii) - Chapter 13 Class 12 Probability (Term 2)

Last updated at Aug. 24, 2021 by

Ex 13.1, 6 - Chapter 13 Class 12 Probability - Part 3

Ex 13.1, 6 - Chapter 13 Class 12 Probability - Part 4

  1. Chapter 13 Class 12 Probability (Term 2)
  2. Serial order wise

    3. Ex 13.1

    Ex 13.2 →

Transcript

Ex 13.1, 6 Determine P(E|F) A coin is tossed three times, where (ii) E : at least two heads , F : at most two heads Coin is tossed three times S = {HHH, HHT, THH, HTH, TTH, THT, HTT, TTT} Coin is tossed three times S = {HHH, HHT, THH, HTH, TTH, THT, HTT, TTT} E : at least two heads E = {HHT, THH, HTH, HHH} P(E) = 4/8=1/2 F : at most two heads F = {HHT, THH, HTH, TTH, THT, HTT, TTT} P(F) = 7/8 Also, E ∩ F = {HHT, THH, HTH} P(E ∩ F ) = 3/8 Now, P(E|F) = (𝑃(𝐸 ∩ 𝐹))/(𝑃(𝐹)) = (3/8)/(7/8) = 3/8 × 8/7 = 3/7 ∴ P(E|F) = 𝟑/𝟕

Chapter 13 Class 12 Probability (Term 2)
Serial order wise

About the Author

Davneet Singh's photo - Teacher, Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.