Ex 13.1, 6 (ii) - Determine P(E|F), E : atleast two heads, F : atmost - Ex 13.1

part 2 - Ex 13.1, 6 (ii) - Ex 13.1 - Serial order wise - Chapter 13 Class 12 Probability

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Ex 13.1, 6 Determine P(E|F) A coin is tossed three times, where (ii) E : at least two heads , F : at most two heads Coin is tossed three times S = {HHH, HHT, THH, HTH, TTH, THT, HTT, TTT} E : at least two heads E = {HHT, THH, HTH, HHH} P(E) = 4/8=1/2 F : at most two heads F = {HHT, THH, HTH, TTH, THT, HTT, TTT} P(F) = 7/8 Also, E ∩ F = {HHT, THH, HTH} P(E ∩ F) = 3/8 Now, P(E|F) = (𝑃(𝐸 ∩ 𝐹))/(𝑃(𝐹)) = (3/8)/(7/8) = 3/8 × 8/7 = 𝟑/𝟕

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo