1. Chapter 13 Class 12 Probability (Term 2)
  2. Serial order wise
  3. Ex 13.1

Ex 13.1, 14 - Chapter 13 Class 12 Probability (Term 2)

Last updated at Feb. 15, 2020 by

Ex 13.1, 14 - Find probability 'sum of numbers on dice is 4'

Ex 13.1, 14 - Chapter 13 Class 12 Probability - Part 2
Ex 13.1, 14 - Chapter 13 Class 12 Probability - Part 3

  1. Chapter 13 Class 12 Probability (Term 2)
  2. Serial order wise

    3. Ex 13.1

    Ex 13.2 →

Transcript

Ex 13.1, 14 Given that the two numbers appearing on throwing two dice are different. Find the probability of the event ‘the sum of numbers on the dice is 4’.Two Dice are thrown We need to find the Probability that the sum of numbers on the dice is 4, given that the two numbers are different. E : Sum of numbers is 4 F : numbers are different We need to find P(E|F) Also, E ∩ F = {(1, 3), (3, 1)} P(E ∩ F) = 2/36 = 1/18 E = {(1, 3), (3, 1), (2, 2)} P(E) = 3/36 = 1/12 Now, P(E|F) = (𝑃(𝐸 ∩ 𝐹))/(𝑃(𝐹)) = (2/36)/(30/36) = 2/30 = 𝟏/𝟏𝟓

Chapter 13 Class 12 Probability (Term 2)
Serial order wise

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