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Ex 13.1, 14 - Chapter 13 Class 12 Probability
Last updated at Aug. 16, 2023 by Teachoo
Ex 13.1
Ex 13.1, 1
Ex 13.1, 2
Ex 13.1, 3 Important
Ex 13.1, 4
Ex 13.1, 5
Ex 13.1, 6 (i)
Ex 13.1, 6 (ii) Important
Ex 13.1, 6 (iii)
Ex 13.1, 7 (i)
Ex 13.1, 7 (ii)
Ex 13.1, 8
Ex 13.1, 9
Ex 13.1, 10 (a) Important
Ex 13.1, 10 (b) Important
Ex 13.1, 11
Ex 13.1, 12 Important
Ex 13.1, 13 Important
Ex 13.1, 14 You are here
Ex 13.1, 15
Ex 13.1, 16 (MCQ) Important
Ex 13.1, 17 (MCQ) Important
Chapter 13 Class 12 Probability
Serial order wise
Transcript
Ex 13.1, 14 Given that the two numbers appearing on throwing two dice are different. Find the probability of the event ‘the sum of numbers on the dice is 4’.Two Dice are thrown We need to find the Probability that the sum of numbers on the dice is 4, given that the two numbers are different. E : Sum of numbers is 4 F : Numbers are different We need to find P(E|F) Also, E ∩ F = {(1, 3), (3, 1)} P(E ∩ F) = 2/36 = 1/18 Event E E = {(1, 3), (3, 1), (2, 2)} P(E) = 3/36 = 1/12 Event F P(F) = 30/36=5/6 Now, P(E|F) = (𝑃(𝐸 ∩ 𝐹))/(𝑃(𝐹)) = (2/36)/(30/36) = 2/30 = 𝟏/𝟏𝟓
