Ex 13.1, 3 - Chapter 13 Class 12 Probability

Last updated at Dec. 16, 2024 by

Ex 13.1, 3 - If P(A) = 0.8, P(B) = 0.5 and P(B|A) = 0.4 - Ex 13.1 - Ex 13.1

part 2 - Ex 13.1, 3 - Ex 13.1 - Serial order wise - Chapter 13 Class 12 Probability

part 3 - Ex 13.1, 3 - Ex 13.1 - Serial order wise - Chapter 13 Class 12 Probability

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Ex 13.1, 3 If P (A) = 0.8, P (B) = 0.5 and P(B|A) = 0.4, find (i) P(A ∩ B)Given P(A) = 0.8 , P(B) = 0.5 & P(B|A) = 0.4 Now, P(B|A) = (𝑃(𝐵 ∩ 𝐴))/(𝑃(𝐴)) 0.4 = (𝑷(𝑨 ∩ 𝑩))/(𝟎. 𝟖) P(A ∩ B) = 0.4 × 0.8 P(A ∩ B) = 0.32 Ex 13.1, 3 If P (A) = 0.8, P (B) = 0.5 and P(B|A) = 0.4, find (ii) P(A|B)P(A|B) = (𝑃(𝐴 ∩ 𝐵))/(𝑃(𝐵)) = (𝟎.𝟑𝟐)/(𝟎.𝟓) = 32/50 = 0.64 Ex 13.1, 3 If P (A) = 0.8, P (B) = 0.5 and P(B|A) = 0.4, find (iii) P(A ∪ B)P(A ∪ B) = P(A) + P(B) – P(A ∩ B) = 0.8 + 0.5 – 0.32 = 1.3 – 0.32 = 0.98

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo