Misc 4 - Chapter 5 Class 12 Continuity and Differentiability
Last updated at May 29, 2018 by Teachoo
Transcript
Misc 4 Differentiate . . . the function, 1 ( ), 0 1 Let = 1 ( ) = 1 ( . 1 2 ) = 1 ( 1 + 1 2 ) = 1 3 2 Differentiating . . . . = 1 ( 3 2 ) = 1 1 3 2 2 3 2 = 1 1 3 3 2 3 2 1 = 1 1 3 3 2 3 2 2 = 1 1 3 3 2 1 2 = 1 1 3 3 2 = 3 2 1 3 Hence =
Finding derivative of Inverse trigonometric functions
Derivative of cos-1 x (Cos inverse x)
Example 26
Example 27
Derivative of cot-1 x (cot inverse x)
Derivative of sec-1 x (Sec inverse x)
Derivative of cosec-1 x (Cosec inverse x)
Ex 5.3, 9
Ex 5.3, 12
Ex 5.3, 14 Important
Ex 5.3, 11
Ex 5.3, 13
Ex 5.3, 10 Important
Ex 5.3, 15
Misc 5
Misc 4 You are here
Misc 13
Chapter 5 Class 12 Continuity and Differentiability
Concept wise
- Checking continuity at a given point
- Checking continuity at any point
- Checking continuity using LHL and RHL
- Algebra of continous functions
- Continuity of composite functions
- Checking if funciton is differentiable
- Finding derivative of a function by chain rule
- Finding derivative of Implicit functions
- Finding derivative of Inverse trigonometric functions
- Finding derivative of Exponential & logarithm functions
- Logarithmic Differentiation - Type 1
- Logarithmic Differentiation - Type 2
- Derivatives in parametric form
- Finding second order derivatives - Normal form
- Finding second order derivatives- Implicit form
- Proofs
- Verify Rolles theorem
- Verify Mean Value Theorem
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.