Last updated at March 11, 2017 by Teachoo

Transcript

Misc 6 Find a vector of magnitude 5 units, and parallel to the resultant of the vectors 𝑎 = 2 𝑖 + 3 𝑗 − 𝑘 and 𝑏 = 𝑖 − 2 𝑗 + 𝑘. 𝑎 = 2 𝑖 + 3 𝑗 − 𝑘 𝑏 = 𝑖 − 2 𝑗 + 𝑘 ( 𝑎 + 𝑏) = (2 + 1) 𝑖 + (3 − 2) 𝑗 + (−1 + 1) 𝑘 = 3 𝑖 + 1 𝑗 + 0 𝑘 Let 𝑐 = ( 𝑎 + 𝑏) ∴ 𝑐 = 3 𝑖 + 1 𝑗 + 0 𝑘 Magnitude of 𝑐 = 32+12+02 𝑐 = 9+1 = 10 Unit vector in direction of 𝑐 = 1 𝑐 × 𝑐 𝑐 = 1 10 × 3 𝑖+1 𝑗+0 𝑘 𝑐 = 𝟑 𝟏𝟎 𝒊 + 𝟏 𝟏𝟎 𝒋 + 0 𝒌 Vector with magnitude 1 = 3 10 𝑖 + 1 10 𝑗 + 0 𝑘 Vector with magnitude 5 = 5 × 3 10 𝑖 + 1 10 𝑗 + 0 𝑘 = 15 10 𝑖 + 2 10 𝑗 + 0 𝑘. = 15 10 𝑖 + 2 10 𝑗. Hence the required vector is 𝟏𝟓 𝟏𝟎 𝒊 + 𝟐 𝟏𝟎 𝒋.

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Misc 6 Important You are here

Misc 12 Important

Misc 13 Important

Misc 15 Important

Misc 19 Important

Class 12

Important Question for exams Class 12

- Chapter 1 Class 12 Relation and Functions
- Chapter 2 Class 12 Inverse Trigonometric Functions
- Chapter 3 Class 12 Matrices
- Chapter 4 Class 12 Determinants
- Chapter 5 Class 12 Continuity and Differentiability
- Chapter 6 Class 12 Application of Derivatives
- Chapter 7 Class 12 Integrals
- Chapter 8 Class 12 Application of Integrals
- Chapter 9 Class 12 Differential Equations
- Chapter 10 Class 12 Vector Algebra
- Chapter 11 Class 12 Three Dimensional Geometry
- Chapter 12 Class 12 Linear Programming
- Chapter 13 Class 12 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.