Misc 6 - Find a vector of magnitude 5 units, parallel to - Miscellaneous

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Misc 6 Find a vector of magnitude 5 units, and parallel to the resultant of the vectors = 2 + 3 and = 2 + . = 2 + 3 = 2 + ( + ) = (2 + 1) + (3 2) + ( 1 + 1) = 3 + 1 + 0 Let = ( + ) = 3 + 1 + 0 Magnitude of = 32+12+02 = 9+1 = 10 Unit vector in direction of = 1 = 1 10 3 +1 +0 = + + 0 Vector with magnitude 1 = 3 10 + 1 10 + 0 Vector with magnitude 5 = 5 3 10 + 1 10 + 0 = 15 10 + 2 10 + 0 . = 15 10 + 2 10 . Hence the required vector is + .

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.