Example 24 - Chapter 10 Class 12 Vector Algebra (Important Question)

Last updated at December 16, 2024 by Teachoo

Example 24 - Find area of a triangle having A (1, 1, 1), B (1, 2, 3)

Example 24 - Chapter 10 Class 12 Vector Algebra - Part 2

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Example 24 Find the area of a triangle having the points A(1, 1, 1), B(1, 2, 3) and C(2, 3, 1) as its vertices. Given A (1, 1, 1) , B (1, 2, 3) ,C (2, 3, 1) Area of triangle ABC = 𝟏/𝟐 |(𝑨𝑩) ⃗ × (𝑨𝑪) ⃗ | Finding AB (𝑨𝑩) ⃗ = (1 − 1) 𝑖 ̂ + (2 − 1) 𝑗 ̂ + (3 − 1) 𝑘 ̂ = 0𝑖 ̂ + 1𝑗 ̂ + 2𝑘 ̂ Finding AC (𝑨𝑪) ⃗ = (2 − 1) 𝑖 ̂ + (3 − 1) 𝑗 ̂ + (1 − 1) 𝑘 ̂ = 1𝑖 ̂ + 2𝑗 ̂ + 0𝑘 ̂ (𝑨𝑩) ⃗ × (𝑨𝑪) ⃗ = |■8(𝑖 ̂&𝑗 ̂&𝑘 ̂@0&1&2@1&2&0)| = 𝑖 ̂ [(1×0)−(2×2)] − 𝑗 ̂[(0×0)−(1×2)] + 𝑘 ̂[(0×2)−(1×1)] = −4𝒊 ̂ + 2𝒋 ̂ – 1𝒌 ̂ Magnitude of (𝐴𝐵) ⃗ × (𝐴𝐶) ⃗ = √((−4)2+22+(−1)2) |(𝑨𝑩) ⃗" × " (𝑨𝑪) ⃗ | = √(16+4+1) = √𝟐𝟏 Therefore, Area of triangle ABC = 1/2 |(𝐴𝐵) ⃗" × " (𝐴𝐶) ⃗ | = 1/2 × √21 = √𝟐𝟏/𝟐

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo

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