Chapter 10 Class 12 Vector Algebra
Chapter 10 Class 12 Vector Algebra
Last updated at December 16, 2024 by Teachoo
Transcript
Ex 10.4, 10 Find the area of the parallelogram whose adjacent sides are determined by the vectors š ā = š Ģ ā š Ģ + 3š Ģ and b = 2š Ģ ā 7š Ģ + š Ģ . š ā = š Ģ ā š Ģ + 3š Ģ = 1š Ģ ā 1š Ģ + 3k Ģ š ā = 2š Ģ ā 7š Ģ + š Ģ = 2š Ģ ā 7š Ģ + 1k Ģ Area of parallelogram ABCD = |š ā" Ć " š ā | š ā Ć š ā = |ā 8(š Ģ&š Ģ&š Ģ@1&ā1&3@2&ā7&1)| = š Ģ (ā1 Ć 1 ā (ā7) Ć 3) ā š Ģ (1 Ć 1 ā 2 Ć 3) + š Ģ (1 Ć ā7 ā 2 Ć ā1) = š Ģ (ā1ā(ā21)) ā š Ģ (1 ā 6) + š Ģ (ā7 ā(ā2)) = š Ģ (ā1 + 21) ā š Ģ (ā5) + š Ģ (ā7 + 2) = 20 š Ģ + 5š Ģ ā 5š Ģ Magnitude of š ā Ć š ā = ā(202+52+(ā5)2) |š ā" Ć " š ā | = ā(400+25+25) = ā450 = ā(25Ć9Ć2) = 5 Ć 3 Ć ā2 = 15 ā2 Therefore, the area of parallelogram is 15āš .