Ex 10.3, 3 - Find projection of vector i - j on vector i + j

Ex 10.3, 3 - Chapter 10 Class 12 Vector Algebra - Part 2

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Ex 10.3, 3 Find the projection of the vector š‘– Ģ‚ āˆ’ š‘— Ģ‚ on the vector š‘– Ģ‚ + š‘— Ģ‚ .Let š‘Ž āƒ— = š‘– Ģ‚ āˆ’ š‘— Ģ‚ = 1š‘– Ģ‚ – 1š‘— Ģ‚ + 0š‘˜ Ģ‚ š‘ āƒ— = š‘– Ģ‚ + š‘— Ģ‚ = 1š‘– Ģ‚ + 1š‘— Ģ‚ + 0š‘˜ Ģ‚ Projector of vector š’‚ āƒ— on š’ƒ āƒ— = šŸ/|š’ƒ āƒ— | (š’‚ āƒ— . š’ƒ āƒ—) Now, š’‚ āƒ— . š’ƒ āƒ— = (1 Ɨ 1) (āˆ’1 Ɨ 1) + (0 Ɨ 0) = 1 + (āˆ’1) + 0 = 0 Also, Magnitude of š‘ āƒ— = √(12+12+02) |š‘ āƒ— | = √(1+1+0) = √2 Projection of š‘Ž āƒ— on š‘ āƒ— = 1/|š‘ āƒ— | (š‘Ž āƒ— . š‘ āƒ—) = 1/√2 (0) = 0

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