1. Class 12
2. Important Question for exams Class 12
3. Chapter 10 Class 12 Vector Algebra

Transcript

Ex 10.3, 10 If ๐๏ทฏ = 2 ๐๏ทฏ + 2 ๐๏ทฏ + 3 ๐๏ทฏ, ๐๏ทฏ = โ ๐๏ทฏ + 2 ๐๏ทฏ + ๐๏ทฏ and ๐๏ทฏ = 3 ๐๏ทฏ + ๐๏ทฏ are such that ๐๏ทฏ +๐ ๐๏ทฏ is perpendicular to ๐๏ทฏ , then find the value of ๐. ๐๏ทฏ = 2 ๐๏ทฏ + 2 ๐๏ทฏ + 3 ๐๏ทฏ ๐๏ทฏ = โ ๐๏ทฏ + 2 ๐๏ทฏ + ๐๏ทฏ = โ1 ๐๏ทฏ + 2 ๐๏ทฏ + 1 ๐๏ทฏ ๐๏ทฏ = 3 ๐๏ทฏ + ๐๏ทฏ = 3 ๐๏ทฏ + 1 ๐๏ทฏ + 0 ๐๏ทฏ ( ๐๏ทฏ + ๐ ๐๏ทฏ) = (2 ๐๏ทฏ + 2 ๐๏ทฏ + 3 ๐๏ทฏ) + ๐ (-1 ๐๏ทฏ + 2 ๐๏ทฏ + 1 ๐๏ทฏ) = 2 ๐๏ทฏ + 2 ๐๏ทฏ + 3 ๐๏ทฏ โ ๐ ๐๏ทฏ + 2๐ ๐๏ทฏ + ๐ ๐๏ทฏ = (2 โ ๐) ๐๏ทฏ + (2 + 2๐) ๐๏ทฏ + (3 + ๐) ๐๏ทฏ If ( ๐๏ทฏ + ๐ ๐๏ทฏ) is perpendicular to ๐๏ทฏ ( ๐๏ทฏ + ๐ ๐๏ทฏ). ๐๏ทฏ = 0 2โ๐๏ทฏ ๐๏ทฏ+ 2+2๐๏ทฏ ๐๏ทฏ+(3+๐) ๐๏ทฏ๏ทฏ . (3 ๐๏ทฏ + 1 ๐๏ทฏ + 0 ๐๏ทฏ) = 0 (2 - ๐).3 + (2 + 2๐).1 + (3 + ๐ ).0 = 0 3.2 โ 3๐ + 2 + 2๐ + 0 = 0 6 โ 3๐ + 2 + 2๐ = 0 8 โ ๐ = 0 ๐ = 8 โด ๐ = 8

Chapter 10 Class 12 Vector Algebra

Class 12
Important Question for exams Class 12