Last updated at May 29, 2018 by Teachoo

Transcript

Ex 10.2, 10 Find a vector in the direction of vector 5 + 2 which has magnitude 8 units. = 5 + 2 = 5 1 + 2 Magnitude of = 52+ 1 2+22 = 25+1+4 = 30 Unit vector in direction of = 1 . = 1 30 . 5 1 +2 = 5 30 1 30 + 2 30 Thus, unit vector = 5 30 1 30 + 2 30 Vector with magnitude 1 = 5 30 1 30 + 2 30 Vector with magnitude 8 = 8 5 30 1 30 + 2 30 = + Hence, the required vector is 40 30 8 30 + 16 30

Ex 10.2, 7
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Ex 10.2, 9 Important

Ex 10.2, 10 Important You are here

Ex 10.2, 13 Important

Ex 10.2, 17 Important

Example 14 Important

Example 16 Important

Example 21 Important

Ex 10.3, 2 Important

Ex 10.3, 3 Important

Ex 10.3, 10 Important

Ex 10.3, 13 Important

Ex 10.3, 16 Important

Example 23 Important

Example 24 Important

Example 25 Important

Ex 10.4, 2 Important

Ex 10.4, 5 Important

Ex 10.4, 9 Important

Ex 10.4, 10 Important

Ex 10.4, 11 Important

Example 28 Important

Example 29 Important

Example 30 Important

Misc 6 Important

Misc 12 Important

Misc 13 Important

Misc 15 Important

Misc 19 Important

Class 12

Important Question for exams Class 12

- Chapter 1 Class 12 Relation and Functions
- Chapter 2 Class 12 Inverse Trigonometric Functions
- Chapter 3 Class 12 Matrices
- Chapter 4 Class 12 Determinants
- Chapter 5 Class 12 Continuity and Differentiability
- Chapter 6 Class 12 Application of Derivatives
- Chapter 7 Class 12 Integrals
- Chapter 8 Class 12 Application of Integrals
- Chapter 9 Class 12 Differential Equations
- Chapter 10 Class 12 Vector Algebra
- Chapter 11 Class 12 Three Dimensional Geometry
- Chapter 12 Class 12 Linear Programming
- Chapter 13 Class 12 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.