Ex 10.4, 9 - Find area of triangle A(1, 1, 2), B(2, 3, 5)

Ex 10.4, 9 - Chapter 10 Class 12 Vector Algebra - Part 2

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Ex 10.4, 9 Find the area of the triangle with vertices A(1, 1, 2), B(2, 3, 5) and C(1, 5, 5). A (1, 1, 2) , B (2, 3, 5) , C (1, 5, 5) Area of triangle ABC is 1/2 |(𝐴𝐵) ⃗ × (𝐴𝐶) ⃗ | A (1, 1, 2) B (2, 3, 5) (𝐴𝐵) ⃗ = (2 − 1) 𝑖 ̂ + (3 − 1) 𝑗 ̂ + (5 − 2) 𝑘 ̂ = 1𝑖 ̂ + 2𝑗 ̂ + 3𝑘 ̂ A (1, 1, 2) C (1, 5, 5) (𝐴𝐶) ⃗ = (1 − 1) 𝑖 ̂ + (5 − 1) 𝑗 ̂ + (5 − 2) 𝑘 ̂ = 0𝑖 ̂ + 4𝑗 ̂ + 3𝑘 ̂ (𝑨𝑩) ⃗ × (𝑨𝑪) ⃗ = |■8(𝑖 ̂&𝑗 ̂&𝑘 ̂@1&2&3@0&4&3)| = 𝑖 ̂ (2×3−4×3 )−𝑗 ̂ (1×3−0×3 )+𝑘 ̂ (1×4−0×2 ) = 𝑖 ̂ (6−12)−𝑗 ̂(3−0) + 𝑘 ̂ (4−0) = −6𝒊 ̂ – 3𝒋 ̂ + 4𝒌 ̂ Magnitude of (𝐴𝐵) ⃗ × (𝐴𝐶) ⃗ = √((−6)2+(−3)2+42) |(𝐴𝐵) ⃗" × " (𝐴𝐶) ⃗ | = √(36+9+16) = √61 Area of triangle ABC = 1/2 |(𝐴𝐵) ⃗" × " (𝐴𝐶) ⃗ | = 1/2 × √61 = √𝟔𝟏/𝟐

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo