Last updated at May 29, 2018 by Teachoo

Transcript

Ex 10.4, 5 Find λ and μ if (2 𝑖 + 6 𝑗 + 27 𝑘) × ( 𝑖 + 𝜆 j + μ 𝑘) = 0 Let 𝑎 = 2 𝑖 + 6 𝑗 + 27 𝑘 & 𝑏 = 1 𝑖 + 𝜆 j + μ 𝑘 Given, 𝑎 × 𝑏 = 0 𝑎 × 𝑏 = 𝑖 𝑗 𝑘 21 6𝜆 27μ = 𝑖 6×μ−(𝜆×27) − 𝑗 2×μ− 1×27 + 𝑘 2×𝜆−(1×6) = 𝑖 6μ−27𝜆 − 𝑗 2μ−27 + 𝑘 2𝜆−6 ∴ 𝑎 × 𝑏 = 6μ−27𝜆 𝑖 − (2μ−27) 𝑗 + (2𝜆 − 6) 𝑘 Also, 𝑎 × 𝑏 = 0 𝟔μ−𝟐𝟕𝜆 𝒊 − (𝟐μ−𝟐𝟕) 𝒋 + (2𝜆 − 6) 𝒌 = 0 𝒊 + 0 𝒋 + 0 𝒌 Comparing components Therefore, 𝜆 = 3 and μ = 𝟐𝟕𝟐

Ex 10.2, 7
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Ex 10.2, 9 Important

Ex 10.2, 10 Important

Ex 10.2, 13 Important

Ex 10.2, 17 Important

Example 14 Important

Example 16 Important

Example 21 Important

Ex 10.3, 2 Important

Ex 10.3, 3 Important

Ex 10.3, 10 Important

Ex 10.3, 13 Important

Ex 10.3, 16 Important

Example 23 Important

Example 24 Important

Example 25 Important

Ex 10.4, 2 Important

Ex 10.4, 5 Important You are here

Ex 10.4, 9 Important

Ex 10.4, 10 Important

Ex 10.4, 11 Important

Example 28 Important

Example 29 Important

Example 30 Important

Misc 6 Important

Misc 12 Important

Misc 13 Important

Misc 15 Important

Misc 19 Important

Class 12

Important Question for exams Class 12

- Chapter 1 Class 12 Relation and Functions
- Chapter 2 Class 12 Inverse Trigonometric Functions
- Chapter 3 Class 12 Matrices
- Chapter 4 Class 12 Determinants
- Chapter 5 Class 12 Continuity and Differentiability
- Chapter 6 Class 12 Application of Derivatives
- Chapter 7 Class 12 Integrals
- Chapter 8 Class 12 Application of Integrals
- Chapter 9 Class 12 Differential Equations
- Chapter 10 Class 12 Vector Algebra
- Chapter 11 Class 12 Three Dimensional Geometry
- Chapter 12 Class 12 Linear Programming
- Chapter 13 Class 12 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.