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Example 4
Example 5 Important
Example 6 Important Deleted for CBSE Board 2023 Exams
Example 7 Important Deleted for CBSE Board 2023 Exams
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Example 11
Example 12 You are here
Example 13 Important Deleted for CBSE Board 2023 Exams
Example 14 Important Deleted for CBSE Board 2023 Exams
Example 15 Important
Last updated at March 16, 2023 by Teachoo
Example 12 Find the area of region bounded by the line =3 +2, the and the ordinates = 1 and =1 First Plotting =3 +2 In graph Area Required = Area ACB + Area ADE Area ACB Area ACB = 1 2 3 equation of line Area ACB = 1 2 3 3 +2 Since Area ACB is below x-axis, it will come negative , Hence, we take modulus Area ACB = 1 2 3 3 +2 = 3 2 2 +2 1 2 3 = 3 2 2 3 2 +2 2 3 3 2 1 2 +2( 1) = 3 2 4 9 4 3 3 2 2 = 2 3 1 2 = 2 3 + 1 2 = 1 6 = 1 6 Area ADE Area ADE = 2 3 1 y equation of line = 2 3 1 3 +2 = 3 2 2 +2 2 3 1 = 3 (1) 2 2 +2 1 3 2 2 3 2 +2 2 3 = 3 2 +2 2 3 4 3 = 7 2 + 2 3 = 25 6 Thus, Required Area = Area ACB + Area ADE = 1 6 + 25 6 = 26 6 = 13 3