


Subscribe to our Youtube Channel - https://you.tube/teachoo
Last updated at Dec. 8, 2016 by Teachoo
Transcript
Step 2 Calculate |A| |A| = 2 1 3 4 = 2(4) ( 1)(3) = 8 + 3 = 11 |A| 0 Thus, System of equation is consistent & has a unique solution Now, AX = B X = A-1 B Step 3 Calculate X = A-1 B A-1 = 1 |A| adj (A) A = 2 1 3 4 adj A = 2 1 3 4 = 4 1 3 2 Now, A-1 = 1 |A| adj A A-1 = 1 11 4 1 3 2 Thus, X = A-1 B = 1 11 4 1 3 2 2 3 = 1 11 4 2 +1(3) 3 2 +2(3) = 1 11 8+3 6+6 = 1 11 5 12 = 5 11 12 11 Hence, x = & y =
Ex 4.6
Ex 4.6, 2 Deleted for CBSE Board 2021 Exams only
Ex 4.6, 3 Important Deleted for CBSE Board 2021 Exams only
Ex 4.6, 4 Deleted for CBSE Board 2021 Exams only
Ex 4.6, 5 Important Deleted for CBSE Board 2021 Exams only
Ex 4.6, 6 Deleted for CBSE Board 2021 Exams only
Ex 4.6, 7 Deleted for CBSE Board 2021 Exams only
Ex 4.6, 8 Deleted for CBSE Board 2021 Exams only You are here
Ex 4.6, 9 Deleted for CBSE Board 2021 Exams only
Ex 4.6, 10 Important Deleted for CBSE Board 2021 Exams only
Ex 4.6, 11 Deleted for CBSE Board 2021 Exams only
Ex 4.6, 12 Deleted for CBSE Board 2021 Exams only
Ex 4.6, 13 Important Deleted for CBSE Board 2021 Exams only
Ex 4.6, 14 Important Deleted for CBSE Board 2021 Exams only
Ex 4.6, 15 Important Deleted for CBSE Board 2021 Exams only
Ex 4.6, 16 Important Deleted for CBSE Board 2021 Exams only
About the Author