# Ex 4.6, 6 - Chapter 4 Class 12 Determinants

Last updated at Dec. 8, 2016 by Teachoo

Last updated at Dec. 8, 2016 by Teachoo

Transcript

Ex 4.6, 6 Examine the consistency of the system of equations. 5x − y + 4z = 5 2x + 3y + 5z = 2 5x − 2y + 6z = −1 The system of equations is 5x − y + 4z = 5 2x + 3y + 5z = 2 5x − 2y + 6z = −1 Step 1 Write about equation as AX = B 5−142355−26 𝑥𝑦𝑧 = 52−1 Hence A = 5−142355−26, X = 𝑥𝑦𝑧 & B = 52−1 Step 2 Calculate |A| |A| = 5−142355−26 = 5 35−26 – 1 ( –1) 2556 + 4 235−2 = 5 (18 + 10) + 1(12 – 25) + 4( – 4 – 15) = 5 (28) + 1 ( –13) + 4( – 19) = 140 – 13 – 78 = 51 ≠ 0 Since |A| ≠ 0 The given system of equation is consistent

Chapter 4 Class 12 Determinants

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.