# Ex 4.6, 4 - Chapter 4 Class 12 Determinants (Term 1)

Last updated at Jan. 23, 2020 by Teachoo

Ex 4.6

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Ex 4.6, 4 Deleted for CBSE Board 2022 Exams You are here

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Ex 4.6, 6 Deleted for CBSE Board 2022 Exams

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Chapter 4 Class 12 Determinants (Term 1)

Serial order wise

Last updated at Jan. 23, 2020 by Teachoo

Ex 4.6, 4 Examine the consistency of the system of equations. x + y + z = 1 2x + 3y + 2z = 2 ax + ay + 2az = 4 Simplifying 3rd equation ax + ay + 2az = 4 a(x + y + 2z) = 4 x + y + 2z = 4/π Now System of equation is x + y + z = 1 2x + 3y + 2z = 2 x + y + 2y = 4/π Writing equation as AX = B [β 8(1&1&1@2&3&2@1&1&2)] [β 8(π₯@π¦@π§)] = [β 8(1@2@4/π)] Hence, A = [β 8(1&1&1@2&3&2@1&1&2)] , X =[β 8(π₯@π¦@π§)] & B =[β 8(1@2@4/π)] Calculating |A| |A| = |β 8(1&1&1@2&3&2@1&1&2)| = 1 |β 8(3&2@1&2)| β1 |β 8(2&2@1&2)| +1|β 8(2&3@1&1)| = 1(6 β 2) β 1(4 β 2) + 1 (2 β 3) = 4 β 2 β 1 = 1 β 0 Since |A| β 0 Hence system of equation is consistent