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Last updated at Jan. 23, 2020 by Teachoo

Transcript

Ex 4.6, 4 Examine the consistency of the system of equations. x + y + z = 1 2x + 3y + 2z = 2 ax + ay + 2az = 4 Simplifying 3rd equation ax + ay + 2az = 4 a(x + y + 2z) = 4 x + y + 2z = 4/๐ Now System of equation is x + y + z = 1 2x + 3y + 2z = 2 x + y + 2y = 4/๐ Writing equation as AX = B [โ 8(1&1&1@2&3&2@1&1&2)] [โ 8(๐ฅ@๐ฆ@๐ง)] = [โ 8(1@2@4/๐)] Hence, A = [โ 8(1&1&1@2&3&2@1&1&2)] , X =[โ 8(๐ฅ@๐ฆ@๐ง)] & B =[โ 8(1@2@4/๐)] Calculating |A| |A| = |โ 8(1&1&1@2&3&2@1&1&2)| = 1 |โ 8(3&2@1&2)| โ1 |โ 8(2&2@1&2)| +1|โ 8(2&3@1&1)| = 1(6 โ 2) โ 1(4 โ 2) + 1 (2 โ 3) = 4 โ 2 โ 1 = 1 โ 0 Since |A| โ 0 Hence system of equation is consistent

Ex 4.6

Ex 4.6, 1
Not in Syllabus - CBSE Exams 2021

Ex 4.6, 2 Not in Syllabus - CBSE Exams 2021

Ex 4.6, 3 Important Not in Syllabus - CBSE Exams 2021

Ex 4.6, 4 Not in Syllabus - CBSE Exams 2021 You are here

Ex 4.6, 5 Important Not in Syllabus - CBSE Exams 2021

Ex 4.6, 6 Not in Syllabus - CBSE Exams 2021

Ex 4.6, 7 Not in Syllabus - CBSE Exams 2021

Ex 4.6, 8 Not in Syllabus - CBSE Exams 2021

Ex 4.6, 9 Not in Syllabus - CBSE Exams 2021

Ex 4.6, 10 Important Not in Syllabus - CBSE Exams 2021

Ex 4.6, 11 Not in Syllabus - CBSE Exams 2021

Ex 4.6, 12 Not in Syllabus - CBSE Exams 2021

Ex 4.6, 13 Important Not in Syllabus - CBSE Exams 2021

Ex 4.6, 14 Important Not in Syllabus - CBSE Exams 2021

Ex 4.6, 15 Important Not in Syllabus - CBSE Exams 2021

Ex 4.6, 16 Important Not in Syllabus - CBSE Exams 2021

Chapter 4 Class 12 Determinants

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.