Slide8.JPG

Slide9.JPG
Slide10.JPG

Go Ad-free

Transcript

Ex 4.5, 4 Examine the consistency of the system of equations. x + y + z = 1 2x + 3y + 2z = 2 ax + ay + 2az = 4 Simplifying 3rd equation ax + ay + 2az = 4 a(x + y + 2z) = 4 x + y + 2z = 4/𝑎 Now System of equation is x + y + z = 1 2x + 3y + 2z = 2 x + y + 2y = 4/𝑎 Writing equation as AX = B [■8(1&1&1@2&3&2@1&1&2)] [■8(𝑥@𝑦@𝑧)] = [■8(1@2@4/𝑎)] Hence, A = [■8(1&1&1@2&3&2@1&1&2)] , X =[■8(𝑥@𝑦@𝑧)] & B =[■8(1@2@4/𝑎)] Calculating |A| |A| = |■8(1&1&1@2&3&2@1&1&2)| = 1 |■8(3&2@1&2)| –1 |■8(2&2@1&2)| +1|■8(2&3@1&1)| = 1(6 – 2) – 1(4 – 2) + 1 (2 – 3) = 4 – 2 – 1 = 1 ≠ 0 Since |A| ≠ 0 Hence system of equation is consistent

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.