Ex 4.6, 3 - Chapter 4 Class 12 Determinants
Last updated at Dec. 8, 2016 by Teachoo
Transcript
Ex 4.6, 3 Step 2 Calculate |A| |A| = 1 3 2 6 = 1(6) 2(3) = 6 6 = 0 Since |A| = 0, we will calculate (adj A) B A = 1 3 2 6 adj (A) = 1 3 2 6 = 6 3 2 1 Now, (adj A)(B) = 6 3 2 1 5 8 = 6 5 + 3 8 2 5 +1(8) = 30 24 10+8 = 6 2 O Since adj A (B) O & |A| = 0, , There exists no solution, Hence the given system of equation is inconsistent
Chapter 4 Class 12 Determinants
Serial order wise
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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.