Ex 4.6, 3 - Chapter 4 Class 12 Determinants (Term 1)

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Ex 4.6, 3 Examine the consistency of the system of equations. x + 3y = 5 2x + 6y = 8 x + 3y = 5 2x + 6y = 8 Writing equation as AX = B [■8(1&[email protected]&6)] [■8(𝑥@𝑦)] = [■8([email protected])] Hence A = [■8(1&[email protected]&6)] , X = [■8(𝑥@𝑦)] & B = [■8([email protected])] Calculating |A| |A| = |■8(1&[email protected]&6)| = 1(6) – 2(3) = 6 – 6 = 0 Since |A| = 0, we will calculate (adj A) B A = [■8(1&[email protected]&6)] adj (A) = [■8(1&[email protected]&6)] = [■8(6&−[email protected]−2&1)] Now, (adj A)(B) = [■8(6&−[email protected]−2&1)] [■8([email protected])] = [■8(6(5)+(⤶7−3)[email protected]−2(5)+1(8))] = [■8(30−[email protected]−10+8)] = [■8([email protected]−2)] ≠ O Since adj A (B) ≠ O & |A| = 0, , There exists no solution, Hence, the given system of equation is inconsistent