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Ex 6.3, 4
Last updated at June 3, 2026 by Teachoo
Class 9
Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar
- Definition (and Quesitons)
- Perimeter of Different Shapes
- Perimeter of a Circle - C/D Ratio
- Pi is Irrational
- Length of an Arc of a Circle
- Problems, Puzzles, and Paradoxes on Perimeter
- Exercise Set 6.1
- Area of Square & Rectangle
- Area of a Parallelogram
- Area of a Triangle
- Heron's Formula
- Circumcircle and Incircle of a Triangle
- Brahmaguptaβs Formula for the Area of a Cyclic 4-gon
- Squaring a Rectangle
- Exercise Set 6.2
- Area of a circle
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Exercise Set 6.3
- End-of-Chapter Exercises
Transcript
Ex 6.4, 4 (i) A chord of a circle of radius 10 cm subtends 90^β at the centre. Find the area of the corresponding: (i) minor sector (that subtends 90^β at the centre). (Use πβ3.14.) Let the minor sector be OAPB Given that Radius = r = 10 cm π=ππΒ° Now, Area of sector OAPB = ΞΈ/(360Β°)Γ Οr2 = 90/360 Γ 3.14 Γ (10)2 = π/π Γ π.ππ Γ πππ = 1/4Γ 314 = 78.5 cm2 Ex 6.4, 4 (ii) A chord of a circle of radius 10 cm subtends 90^β at the centre. Find the area of the corresponding: (ii) major sector (that subtends 270^β at the centre). (Use πβ3.14.) Area of major sector = Area of circle β Area of sector OAPB Now, Area of circle = Οr2 = 3.14 Γ (10)2 = 3.14 Γ 100 = 314 cm2 Now, Area of major sector = Area of circle β Area of sector OAPB = 314 β 78.5 = 235.5 cm2
