Find the sums and differences: (c) 15 6/10  4/100+14 3/10 6/100 - Figure it out - Page 58

part 2 - Question (c) - Figure it out - Page 58 - Chapter 3 Class 7 - A peek beyond the Point (Ganita Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT)

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Question (c) Find the sums and differences: (c) 15 6/10 4/100+14 3/10 6/100 These are mixed fractions, converting them into normal fractions 15 6/10 4/100=15+6/10+4/100=(15 Ɨ 100 + 6 Ɨ 10 + 4)/100=šŸšŸ“šŸ”šŸ’/šŸšŸŽšŸŽ 14 3/10 6/100=14+3/10+6/100=(14 Ɨ 100 + 3 Ɨ 10 + 6)/100=šŸšŸ’šŸ‘šŸ”/šŸšŸŽšŸŽ Now, adding šŸšŸ“šŸ”šŸ’/šŸšŸŽšŸŽ and šŸšŸ’šŸ‘šŸ”/šŸšŸŽšŸŽ Since denominator is same, we add numerator šŸšŸ“šŸ”šŸ’/šŸšŸŽšŸŽ +šŸšŸ’šŸ‘šŸ”/šŸšŸŽšŸŽ=(1564 + 1436)/100 =šŸ‘šŸŽšŸŽšŸŽ/šŸšŸŽšŸŽ =šŸ‘šŸŽ

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