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Question 31 - CBSE Class 10 Sample Paper for 2023 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at Dec. 13, 2024 by

Two coins are tossed simultaneously. What is the probability of getting

(i)  At least one head?

(ii) At most one tail?

(iii) A head and a tail?

 

This question is Similar to Question 6 - Past Year MCQ - Chapter 15 Class 10

 

[Class 10] Two coins are tossed simultaneously. What is probability - CBSE Class 10 Sample Paper for 2023 Boards - Maths Standard

part 2 - Question 31 - CBSE Class 10 Sample Paper for 2023 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10
part 3 - Question 31 - CBSE Class 10 Sample Paper for 2023 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10 part 4 - Question 31 - CBSE Class 10 Sample Paper for 2023 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

 

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Transcript

Question 31 Two coins are tossed simultaneously. What is the probability of getting (i) At least one head? (ii) At most one tail? (iii) A head and a tail?When 2 coins are tossed Possible outcomes = HH, TH, HT, TT Let’s solve each part individually (i) At least one head? Now, Outcomes with atleast with 1 head = HH, HT, TH Thus, P(getting atleast 1 head) = (π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘œπ‘’π‘‘π‘π‘œπ‘šπ‘’π‘  π‘€π‘–π‘‘β„Ž π‘Žπ‘‘π‘™π‘’π‘Žπ‘ π‘‘ 1 β„Žπ‘’π‘Žπ‘‘)/(π‘‡π‘œπ‘‘π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘œπ‘’π‘‘π‘π‘œπ‘šπ‘’π‘ ) = πŸ‘/πŸ’(ii) At most one tail? Now, Outcomes with atmost with 1 tail = HH, HT, TH Thus, P(getting atmost 1 tail) = (π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘œπ‘’π‘‘π‘π‘œπ‘šπ‘’π‘  π‘€π‘–π‘‘β„Ž π‘Žπ‘‘π‘šπ‘œπ‘ π‘‘ 1 π‘‘π‘Žπ‘–π‘™)/(π‘‡π‘œπ‘‘π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘œπ‘’π‘‘π‘π‘œπ‘šπ‘’π‘ ) = πŸ‘/πŸ’ (iii) A head and a tail? Now, Outcomes with a head and a tail = HT, TH Thus, P(getting with a head and a tail ) = (π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘œπ‘’π‘‘π‘π‘œπ‘šπ‘’π‘  π‘€π‘–π‘‘β„Ž π‘Ž β„Žπ‘’π‘Žπ‘‘ π‘Žπ‘›π‘‘ π‘Ž π‘‘π‘Žπ‘–π‘™)/(π‘‡π‘œπ‘‘π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘œπ‘’π‘‘π‘π‘œπ‘šπ‘’π‘ ) = 2/4 = 𝟏/𝟐

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo