Question 6 Two different coins are tossed simultaneously. The probability of getting at least one head is: (a) 1/4 (b) 1/8 (c) 3/4 (d) 7/8 When 2 coins are tossed
Possible outcomes = HH, TH, HT, TT
Now,
Outcomes with atleast with 1 head = HH, HT, TH
Thus,
P(getting atleast 1 head)
= (๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐ก๐๐๐๐๐ ๐ค๐๐กโ ๐๐ก๐๐๐๐ ๐ก 1 โ๐๐๐)/(๐๐๐ก๐๐ ๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐ก๐๐๐๐๐ )
= ๐/๐
So, the correct answer is (C)
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