Question 6

Two different coins are tossed simultaneously. The  probability of getting at least one head is:

(a) 1/4                                                               (b) 1/8

(c) 3/4                                                               (d) 7/8

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Transcript

Question 6 Two different coins are tossed simultaneously. The probability of getting at least one head is: (a) 1/4 (b) 1/8 (c) 3/4 (d) 7/8 When 2 coins are tossed Possible outcomes = HH, TH, HT, TT Now, Outcomes with atleast with 1 head = HH, HT, TH Thus, P(getting atleast 1 head) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘œ๐‘ข๐‘ก๐‘๐‘œ๐‘š๐‘’๐‘  ๐‘ค๐‘–๐‘กโ„Ž ๐‘Ž๐‘ก๐‘™๐‘’๐‘Ž๐‘ ๐‘ก 1 โ„Ž๐‘’๐‘Ž๐‘‘)/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘œ๐‘ข๐‘ก๐‘๐‘œ๐‘š๐‘’๐‘ ) = ๐Ÿ‘/๐Ÿ’ So, the correct answer is (C)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.