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Question 3
In a family of 3 children, the probability of having at least one boy is:
(a) 7/8 (b) 1/8
(c) 5/8 (d) 3/4
Question 3 - Past Year MCQ - Chapter 14 Class 10 Probability
Last updated at April 16, 2024 by Teachoo
Chapter 14 Class 10 Probability
Serial order wise
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Transcript
Question 3 In a family of 3 children, the probability of having at least one boy is: (a) 7/8 (b) 1/8 (c) 5/8 (d) 3/4 In a family of 3 children, the possible outcomes are BBB BBG BGB GBB BGG GBG GGB GGG Thus, Total number of outcomes = 8 Number of outcomes with atleast one boy = 7 Now, P(atleast one boy) = (๐(๐ด))/(๐(๐)) = 7/8 So, the correct answer is (a) Thus, Total number of outcomes = 8 Number of outcomes with atleast one boy = 7 Now, P(atleast one boy) = (๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐ก๐๐๐๐๐ ๐ค๐๐กโ ๐๐ก๐๐๐๐ ๐ก 1 ๐๐๐ฆ)/(๐๐๐ก๐๐ ๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐ก๐๐๐๐๐ ) = ๐/๐ So, the correct answer is (a)
