Question 3

In a family of 3 children, the probability of having at least one boy is:

(a) 7/8                                                          (b) 1/8

(c) 5/8                                                          (d) 3/4

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  1. Chapter 15 Class 10 Probability (Term 1)
  2. Serial order wise

Transcript

Question 3 In a family of 3 children, the probability of having at least one boy is: (a) 7/8 (b) 1/8 (c) 5/8 (d) 3/4 In a family of 3 children, the possible outcomes are BBB BBG BGB GBB BGG GBG GGB GGG Thus, Total number of outcomes = 8 Number of outcomes with atleast one boy = 7 Now, P(atleast one boy) = (๐‘›(๐ด))/(๐‘›(๐‘†)) = 7/8 So, the correct answer is (a) Thus, Total number of outcomes = 8 Number of outcomes with atleast one boy = 7 Now, P(atleast one boy) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘œ๐‘ข๐‘ก๐‘๐‘œ๐‘š๐‘’๐‘  ๐‘ค๐‘–๐‘กโ„Ž ๐‘Ž๐‘ก๐‘™๐‘’๐‘Ž๐‘ ๐‘ก 1 ๐‘๐‘œ๐‘ฆ)/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘œ๐‘ข๐‘ก๐‘๐‘œ๐‘š๐‘’๐‘ ) = ๐Ÿ•/๐Ÿ– So, the correct answer is (a)

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.