ABCD is a trapezium with AD ∥ BC and AD = 4 cm. If the diagonals AC and BD intersect each other at O such that AO/OC = DO/OB = 1/2, then BC =

(a) 6 cm   (b) 7 cm  (c) 8 cm  (d) 9 cm

 

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ABCD is a trapezium with AD ∥ BC and AD = 4 cm. If the diagonals AC and BD intersect each other at O such that AO/OC = DO/OB = 1/2, then BC = (a) 6 cm (b) 7 cm (c) 8 cm (d) 9 cm In Δ AOD and Δ BOC ∠ AOD = ∠ BOC 𝐴𝑂/𝑂𝐶=𝐷𝑂/𝑂𝐵 ∴ Δ AOD ~ Δ BOC Since both triangles are similar Their sides will be in proportion 𝑨𝑶/𝑶𝑪=𝑫𝑶/𝑶𝑩=𝑨𝑫/𝑩𝑪 1/2=𝐴𝐷/𝐵𝐶 Putting AD = 4 cm 1/2=4/𝐵𝐶 BC = 2 × 4 BC = 8 cm So, the correct answer is (c)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.