Question 34 (Choice 1) - CBSE Class 10 Sample Paper for 2023 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at May 29, 2023 by Teachoo

Due to heavy floods in a state, thousands were rendered homeless. 50 schools collectively decided to provide place and the canvas for 1500 tents and share the whole expenditure equally. The lower part of each tent is cylindrical with base radius 2.8 m and height 3.5 m and the upper part is conical with the same base radius, but of height 2.1 m. If the canvas used to make the tents costs ₹120 per m
^{
2
}
, find the amount shared by each school to set up the tents

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class

Question 34 (Choice 1) Due to heavy floods in a state, thousands were rendered homeless. 50 schools collectively decided to provide place and the canvas for 1500 tents and share the whole expenditure equally. The lower part of each tent is cylindrical with base radius 2.8 m and height 3.5 m and the upper part is conical with the same base radius, but of height 2.1 m. If the canvas used to make the tents costs ₹120 per m2 , find the amount shared by each school to set up the tentsWe need to find amount shared by each school to set up the tents
Amount Shared = (𝑇𝑜𝑡𝑎𝑙 𝐶𝑜𝑠𝑡 𝑜𝑓 𝑚𝑎𝑘𝑖𝑛𝑔 1500 𝑡𝑒𝑛𝑡𝑠)/(𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑆𝑐ℎ𝑜𝑜𝑙𝑠)
= (1500 × 𝑇𝑜𝑡𝑎𝑙 𝐶𝑜𝑠𝑡 𝑜𝑓 𝑚𝑎𝑘𝑖𝑛𝑔 1 𝑡𝑒𝑛𝑡)/50
= 30 × Total cost of making 1 tent
Now,
Total cost of making 1 tent
= Rate × Area of material required
= 120 × (CSA of cone + CSA of cylinder)Curved Surface Area of Cone
Radius of cone = 2.8 cm
Height of cone = 2.1 cm
We need to find slant height l
l = √(𝑟^2+ℎ^2 )
l = √(〖(2.8)〗^2 + 〖(2.1)〗^2 )
l = √(((4 × 7)/10)^2+((3 × 7)/10)^2 )
l = √((7/10)^2 [4^2+3^2 ] )
l = 7/10 √((16+9))
l = 7/10 √25
l = 7/10 × 5
l = 3.5 m
l = 7/10 × 5
l = 3.5 m
Now,
Curved Surface area of cone = 𝜋𝑟𝑙
= 𝜋 × 2.8 × 3.5
= 22/7×28/10 ×35/10
= 22 ×4/10 ×35/10
= 30.8 m2Curved Surface Area of Cylinder
Radius of cylinder = 2.8 cm
Height of cylinder = 3.5 cm
Now,
Curved Surface area of cylinder = 2𝜋𝑟ℎ
= 2 × 𝜋 × 2.8 × 3.5
= 2 × 22/7×28/10 ×35/10
= 2 × 22 ×4/10 ×35/10
= 61.6 m2
Now,
Total cost of making 1 tent = 120 × (CSA of cone + CSA of cylinder)
= 120 × (61.6 + 30.8)
= 120 × 92.4
= Rs 11,088
Therefore,
Amount Shared = 30 × Total cost of making 1 tent
= 30 × 11088
= Rs 3,32,640

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

Hi, it looks like you're using AdBlock :(

Displaying ads are our only source of revenue. To help Teachoo create more content, and view the ad-free version of Teachooo... please purchase Teachoo Black subscription.

Please login to view more pages. It's free :)

Teachoo gives you a better experience when you're logged in. Please login :)

Solve all your doubts with Teachoo Black!

Teachoo answers all your questions if you are a Black user!